3.2.62 \(\int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx\) [162]

3.2.62.1 Optimal result
3.2.62.2 Mathematica [A] (verified)
3.2.62.3 Rubi [A] (verified)
3.2.62.4 Maple [F]
3.2.62.5 Fricas [F]
3.2.62.6 Sympy [F(-1)]
3.2.62.7 Maxima [F]
3.2.62.8 Giac [F]
3.2.62.9 Mupad [F(-1)]

3.2.62.1 Optimal result

Integrand size = 35, antiderivative size = 504 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {(2-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{3 \text {d1}^2 \text {d2}^2 f \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}-\frac {(2-m) m (f x)^{1+m} \sqrt {1-c^2 x^2} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f (1+m) \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}+\frac {b c (2-m) (f x)^{2+m} \sqrt {-1+c x} \sqrt {1+c x} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (2+m) \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}+\frac {b c (f x)^{2+m} \sqrt {-1+c x} \sqrt {1+c x} \operatorname {Hypergeometric2F1}\left (2,\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (2+m) \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}-\frac {b c (2-m) m (f x)^{2+m} \sqrt {-1+c x} \sqrt {1+c x} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (1+m) (2+m) \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}} \]

output
1/3*(f*x)^(1+m)*(a+b*arccosh(c*x))/d1/d2/f/(c*d1*x+d1)^(3/2)/(-c*d2*x+d2)^ 
(3/2)+1/3*(2-m)*(f*x)^(1+m)*(a+b*arccosh(c*x))/d1^2/d2^2/f/(c*d1*x+d1)^(1/ 
2)/(-c*d2*x+d2)^(1/2)+1/3*b*c*(2-m)*(f*x)^(2+m)*hypergeom([1, 1+1/2*m],[2+ 
1/2*m],c^2*x^2)*(c*x-1)^(1/2)*(c*x+1)^(1/2)/d1^2/d2^2/f^2/(2+m)/(c*d1*x+d1 
)^(1/2)/(-c*d2*x+d2)^(1/2)+1/3*b*c*(f*x)^(2+m)*hypergeom([2, 1+1/2*m],[2+1 
/2*m],c^2*x^2)*(c*x-1)^(1/2)*(c*x+1)^(1/2)/d1^2/d2^2/f^2/(2+m)/(c*d1*x+d1) 
^(1/2)/(-c*d2*x+d2)^(1/2)-1/3*b*c*(2-m)*m*(f*x)^(2+m)*hypergeom([1, 1+1/2* 
m, 1+1/2*m],[2+1/2*m, 3/2+1/2*m],c^2*x^2)*(c*x-1)^(1/2)*(c*x+1)^(1/2)/d1^2 
/d2^2/f^2/(1+m)/(2+m)/(c*d1*x+d1)^(1/2)/(-c*d2*x+d2)^(1/2)-1/3*(2-m)*m*(f* 
x)^(1+m)*(a+b*arccosh(c*x))*hypergeom([1/2, 1/2+1/2*m],[3/2+1/2*m],c^2*x^2 
)*(-c^2*x^2+1)^(1/2)/d1^2/d2^2/f/(1+m)/(c*d1*x+d1)^(1/2)/(-c*d2*x+d2)^(1/2 
)
 
3.2.62.2 Mathematica [A] (verified)

Time = 0.74 (sec) , antiderivative size = 413, normalized size of antiderivative = 0.82 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\frac {x (f x)^m \left ((1+m) (2+m) \left (2+3 m+m^2\right ) (a+b \text {arccosh}(c x))-b c (1+m) \left (2+3 m+m^2\right ) x (-1+c x)^{3/2} (1+c x)^{3/2} \operatorname {Hypergeometric2F1}\left (2,1+\frac {m}{2},2+\frac {m}{2},c^2 x^2\right )+(2-m) (2+m) (1-c x) (1+c x) \left ((1+m)^2 (2+m) (a+b \text {arccosh}(c x))+b c (1+m)^2 x \sqrt {-1+c x} \sqrt {1+c x} \operatorname {Hypergeometric2F1}\left (1,1+\frac {m}{2},2+\frac {m}{2},c^2 x^2\right )-m \left (a \left (2+3 m+m^2\right ) \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )+b \left (2+3 m+m^2\right ) \sqrt {1-c^2 x^2} \text {arccosh}(c x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )+b c (1+m) x \sqrt {-1+c x} \sqrt {1+c x} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )\right )\right )\right )}{3 \text {d1}^2 \text {d2}^2 (1+m) (2+m) \left (2+3 m+m^2\right ) (1-c x) (1+c x) \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}} \]

input
Integrate[((f*x)^m*(a + b*ArcCosh[c*x]))/((d1 + c*d1*x)^(5/2)*(d2 - c*d2*x 
)^(5/2)),x]
 
output
(x*(f*x)^m*((1 + m)*(2 + m)*(2 + 3*m + m^2)*(a + b*ArcCosh[c*x]) - b*c*(1 
+ m)*(2 + 3*m + m^2)*x*(-1 + c*x)^(3/2)*(1 + c*x)^(3/2)*Hypergeometric2F1[ 
2, 1 + m/2, 2 + m/2, c^2*x^2] + (2 - m)*(2 + m)*(1 - c*x)*(1 + c*x)*((1 + 
m)^2*(2 + m)*(a + b*ArcCosh[c*x]) + b*c*(1 + m)^2*x*Sqrt[-1 + c*x]*Sqrt[1 
+ c*x]*Hypergeometric2F1[1, 1 + m/2, 2 + m/2, c^2*x^2] - m*(a*(2 + 3*m + m 
^2)*Sqrt[1 - c^2*x^2]*Hypergeometric2F1[1/2, (1 + m)/2, (3 + m)/2, c^2*x^2 
] + b*(2 + 3*m + m^2)*Sqrt[1 - c^2*x^2]*ArcCosh[c*x]*Hypergeometric2F1[1/2 
, (1 + m)/2, (3 + m)/2, c^2*x^2] + b*c*(1 + m)*x*Sqrt[-1 + c*x]*Sqrt[1 + c 
*x]*HypergeometricPFQ[{1, 1 + m/2, 1 + m/2}, {3/2 + m/2, 2 + m/2}, c^2*x^2 
]))))/(3*d1^2*d2^2*(1 + m)*(2 + m)*(2 + 3*m + m^2)*(1 - c*x)*(1 + c*x)*Sqr 
t[d1 + c*d1*x]*Sqrt[d2 - c*d2*x])
 
3.2.62.3 Rubi [A] (verified)

Time = 1.84 (sec) , antiderivative size = 484, normalized size of antiderivative = 0.96, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.229, Rules used = {6352, 82, 278, 6352, 25, 82, 278, 6364}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(c \text {d1} x+\text {d1})^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx\)

\(\Big \downarrow \) 6352

\(\displaystyle \frac {(2-m) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(c x \text {d1}+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}dx}{3 \text {d1} \text {d2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} \int \frac {(f x)^{m+1}}{(1-c x)^2 (c x+1)^2}dx}{3 \text {d1}^2 \text {d2}^2 f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}\)

\(\Big \downarrow \) 82

\(\displaystyle \frac {(2-m) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(c x \text {d1}+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}dx}{3 \text {d1} \text {d2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} \int \frac {(f x)^{m+1}}{\left (1-c^2 x^2\right )^2}dx}{3 \text {d1}^2 \text {d2}^2 f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}\)

\(\Big \downarrow \) 278

\(\displaystyle \frac {(2-m) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(c x \text {d1}+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}dx}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

\(\Big \downarrow \) 6352

\(\displaystyle \frac {(2-m) \left (-\frac {m \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\sqrt {c x \text {d1}+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}dx}{\text {d1} \text {d2}}-\frac {b c \sqrt {c x-1} \sqrt {c x+1} \int -\frac {(f x)^{m+1}}{(1-c x) (c x+1)}dx}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {(2-m) \left (-\frac {m \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\sqrt {c x \text {d1}+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}dx}{\text {d1} \text {d2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} \int \frac {(f x)^{m+1}}{(1-c x) (c x+1)}dx}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

\(\Big \downarrow \) 82

\(\displaystyle \frac {(2-m) \left (-\frac {m \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\sqrt {c x \text {d1}+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}dx}{\text {d1} \text {d2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} \int \frac {(f x)^{m+1}}{1-c^2 x^2}dx}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

\(\Big \downarrow \) 278

\(\displaystyle \frac {(2-m) \left (-\frac {m \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\sqrt {c x \text {d1}+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}dx}{\text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (1,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{\text {d1} \text {d2} f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

\(\Big \downarrow \) 6364

\(\displaystyle \frac {(2-m) \left (-\frac {m \left (\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \, _3F_2\left (1,\frac {m}{2}+1,\frac {m}{2}+1;\frac {m}{2}+\frac {3}{2},\frac {m}{2}+2;c^2 x^2\right )}{f^2 (m+1) (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {\sqrt {1-c^2 x^2} (f x)^{m+1} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},c^2 x^2\right ) (a+b \text {arccosh}(c x))}{f (m+1) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{\text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{\text {d1} \text {d2} f \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (1,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{\text {d1} \text {d2} f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\right )}{3 \text {d1} \text {d2}}+\frac {(f x)^{m+1} (a+b \text {arccosh}(c x))}{3 \text {d1} \text {d2} f (c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2}}+\frac {b c \sqrt {c x-1} \sqrt {c x+1} (f x)^{m+2} \operatorname {Hypergeometric2F1}\left (2,\frac {m+2}{2},\frac {m+4}{2},c^2 x^2\right )}{3 \text {d1}^2 \text {d2}^2 f^2 (m+2) \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x}}\)

input
Int[((f*x)^m*(a + b*ArcCosh[c*x]))/((d1 + c*d1*x)^(5/2)*(d2 - c*d2*x)^(5/2 
)),x]
 
output
((f*x)^(1 + m)*(a + b*ArcCosh[c*x]))/(3*d1*d2*f*(d1 + c*d1*x)^(3/2)*(d2 - 
c*d2*x)^(3/2)) + (b*c*(f*x)^(2 + m)*Sqrt[-1 + c*x]*Sqrt[1 + c*x]*Hypergeom 
etric2F1[2, (2 + m)/2, (4 + m)/2, c^2*x^2])/(3*d1^2*d2^2*f^2*(2 + m)*Sqrt[ 
d1 + c*d1*x]*Sqrt[d2 - c*d2*x]) + ((2 - m)*(((f*x)^(1 + m)*(a + b*ArcCosh[ 
c*x]))/(d1*d2*f*Sqrt[d1 + c*d1*x]*Sqrt[d2 - c*d2*x]) + (b*c*(f*x)^(2 + m)* 
Sqrt[-1 + c*x]*Sqrt[1 + c*x]*Hypergeometric2F1[1, (2 + m)/2, (4 + m)/2, c^ 
2*x^2])/(d1*d2*f^2*(2 + m)*Sqrt[d1 + c*d1*x]*Sqrt[d2 - c*d2*x]) - (m*(((f* 
x)^(1 + m)*Sqrt[1 - c^2*x^2]*(a + b*ArcCosh[c*x])*Hypergeometric2F1[1/2, ( 
1 + m)/2, (3 + m)/2, c^2*x^2])/(f*(1 + m)*Sqrt[d1 + c*d1*x]*Sqrt[d2 - c*d2 
*x]) + (b*c*(f*x)^(2 + m)*Sqrt[-1 + c*x]*Sqrt[1 + c*x]*HypergeometricPFQ[{ 
1, 1 + m/2, 1 + m/2}, {3/2 + m/2, 2 + m/2}, c^2*x^2])/(f^2*(1 + m)*(2 + m) 
*Sqrt[d1 + c*d1*x]*Sqrt[d2 - c*d2*x])))/(d1*d2)))/(3*d1*d2)
 

3.2.62.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 82
Int[((a_) + (b_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_) 
)^(p_.), x_] :> Int[(a*c + b*d*x^2)^m*(e + f*x)^p, x] /; FreeQ[{a, b, c, d, 
 e, f, m, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[n, m] && IntegerQ[m]
 

rule 278
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[a^p*(( 
c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/2, (m + 1)/2 + 1, ( 
-b)*(x^2/a)], x] /; FreeQ[{a, b, c, m, p}, x] &&  !IGtQ[p, 0] && (ILtQ[p, 0 
] || GtQ[a, 0])
 

rule 6352
Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d1_) + (e 
1_.)*(x_))^(p_)*((d2_) + (e2_.)*(x_))^(p_), x_Symbol] :> Simp[(-(f*x)^(m + 
1))*(d1 + e1*x)^(p + 1)*(d2 + e2*x)^(p + 1)*((a + b*ArcCosh[c*x])^n/(2*d1*d 
2*f*(p + 1))), x] + (Simp[(m + 2*p + 3)/(2*d1*d2*(p + 1))   Int[(f*x)^m*(d1 
 + e1*x)^(p + 1)*(d2 + e2*x)^(p + 1)*(a + b*ArcCosh[c*x])^n, x], x] - Simp[ 
b*c*(n/(2*f*(p + 1)))*Simp[(d1 + e1*x)^p/(1 + c*x)^p]*Simp[(d2 + e2*x)^p/(- 
1 + c*x)^p]   Int[(f*x)^(m + 1)*(1 + c*x)^(p + 1/2)*(-1 + c*x)^(p + 1/2)*(a 
 + b*ArcCosh[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d1, e1, d2, e2, f, m 
}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] && GtQ[n, 0] && LtQ[p, -1] &&  ! 
GtQ[m, 1] && (IntegerQ[m] || EqQ[n, 1])
 

rule 6364
Int[(((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_))/(Sqrt[(d1_) + ( 
e1_.)*(x_)]*Sqrt[(d2_) + (e2_.)*(x_)]), x_Symbol] :> Simp[((f*x)^(m + 1)/(f 
*(m + 1)))*Simp[Sqrt[1 - c^2*x^2]/(Sqrt[d1 + e1*x]*Sqrt[d2 + e2*x])]*(a + b 
*ArcCosh[c*x])*Hypergeometric2F1[1/2, (1 + m)/2, (3 + m)/2, c^2*x^2], x] + 
Simp[b*c*((f*x)^(m + 2)/(f^2*(m + 1)*(m + 2)))*Simp[Sqrt[1 + c*x]/Sqrt[d1 + 
 e1*x]]*Simp[Sqrt[-1 + c*x]/Sqrt[d2 + e2*x]]*HypergeometricPFQ[{1, 1 + m/2, 
 1 + m/2}, {3/2 + m/2, 2 + m/2}, c^2*x^2], x] /; FreeQ[{a, b, c, d1, e1, d2 
, e2, f, m}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] &&  !IntegerQ[m]
 
3.2.62.4 Maple [F]

\[\int \frac {\left (f x \right )^{m} \left (a +b \,\operatorname {arccosh}\left (c x \right )\right )}{\left (c \operatorname {d1} x +\operatorname {d1} \right )^{\frac {5}{2}} \left (-c \operatorname {d2} x +\operatorname {d2} \right )^{\frac {5}{2}}}d x\]

input
int((f*x)^m*(a+b*arccosh(c*x))/(c*d1*x+d1)^(5/2)/(-c*d2*x+d2)^(5/2),x)
 
output
int((f*x)^m*(a+b*arccosh(c*x))/(c*d1*x+d1)^(5/2)/(-c*d2*x+d2)^(5/2),x)
 
3.2.62.5 Fricas [F]

\[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\int { \frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c d_{1} x + d_{1}\right )}^{\frac {5}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((f*x)^m*(a+b*arccosh(c*x))/(c*d1*x+d1)^(5/2)/(-c*d2*x+d2)^(5/2), 
x, algorithm="fricas")
 
output
integral(-sqrt(c*d1*x + d1)*sqrt(-c*d2*x + d2)*(b*arccosh(c*x) + a)*(f*x)^ 
m/(c^6*d1^3*d2^3*x^6 - 3*c^4*d1^3*d2^3*x^4 + 3*c^2*d1^3*d2^3*x^2 - d1^3*d2 
^3), x)
 
3.2.62.6 Sympy [F(-1)]

Timed out. \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\text {Timed out} \]

input
integrate((f*x)**m*(a+b*acosh(c*x))/(c*d1*x+d1)**(5/2)/(-c*d2*x+d2)**(5/2) 
,x)
 
output
Timed out
 
3.2.62.7 Maxima [F]

\[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\int { \frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c d_{1} x + d_{1}\right )}^{\frac {5}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((f*x)^m*(a+b*arccosh(c*x))/(c*d1*x+d1)^(5/2)/(-c*d2*x+d2)^(5/2), 
x, algorithm="maxima")
 
output
integrate((b*arccosh(c*x) + a)*(f*x)^m/((c*d1*x + d1)^(5/2)*(-c*d2*x + d2) 
^(5/2)), x)
 
3.2.62.8 Giac [F]

\[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\int { \frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c d_{1} x + d_{1}\right )}^{\frac {5}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((f*x)^m*(a+b*arccosh(c*x))/(c*d1*x+d1)^(5/2)/(-c*d2*x+d2)^(5/2), 
x, algorithm="giac")
 
output
integrate((b*arccosh(c*x) + a)*(f*x)^m/((c*d1*x + d1)^(5/2)*(-c*d2*x + d2) 
^(5/2)), x)
 
3.2.62.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{(\text {d1}+c \text {d1} x)^{5/2} (\text {d2}-c \text {d2} x)^{5/2}} \, dx=\int \frac {\left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )\,{\left (f\,x\right )}^m}{{\left (d_{1}+c\,d_{1}\,x\right )}^{5/2}\,{\left (d_{2}-c\,d_{2}\,x\right )}^{5/2}} \,d x \]

input
int(((a + b*acosh(c*x))*(f*x)^m)/((d1 + c*d1*x)^(5/2)*(d2 - c*d2*x)^(5/2)) 
,x)
 
output
int(((a + b*acosh(c*x))*(f*x)^m)/((d1 + c*d1*x)^(5/2)*(d2 - c*d2*x)^(5/2)) 
, x)